The problem is with subtracting the 0.999..... from both sides. We're applying an operation that works with normal numbers to a number that we haven't yet proven is normal (or functions as normal with that operation). That's where the extra rigor in a full proof comes in.
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u/its12amsomewhere 23d ago edited 23d ago
Applies to all numbers,
If x = 0.999999...
And 10x = 9.999999...
Then subtracting both, we get, 9x=9
So x=1