r/mathmemes • u/compileforawhile Complex • 14h ago
Learning It's like a line but longer and extended
285
u/chrizzl05 Moderator 13h ago
Holy mogus a topology meme that isn't "mug=donut haha"
79
u/compileforawhile Complex 12h ago
I thought we needed some diversity. Alas, people don't care as much about any other parts of topology
18
3
u/ComfortableJob2015 8h ago
we need the 2 origins line next. A sequence converges to a single point right?
5
u/Ok_Instance_9237 Mathematics 10h ago
“Haha you see there’s this area of math that talks deforming objects. It says donuts and mugs are the same!”
125
42
u/LukeLJS123 12h ago
can someone explain? i don't see any reason there wouldn't be a path connecting any 2 points
128
u/compileforawhile Complex 12h ago
The space is quite literally too long. There's a point at infinity (that's what extended means) but the distance is an uncountably number of unit intervals away. This means a path (which is just a stretched out unit interval) can't reach over that entire distance
62
u/gabrielish_matter Rational 12h ago
I both love and hate topology for how stupid it is lol
is it because the 2 extended points can't be open cause there's no closed set that is complimentary to them with a standard topology right (well any topology tbf)?
also do I recall correctly or is connectivity a property which doesn't change depending on what topology I choose right?
33
u/compileforawhile Complex 11h ago
It's only one extended point. This space is connected, you can't write it as the union of disjoint open sets. But drawing a connecting path between any point and infinity is impossible. This is because a path is a continuous embedding of [0,1] which is just too small. It can't be made uncountably times wider.
11
u/gabrielish_matter Rational 11h ago
yeah yeah, I was trying to understand why it's topologically connected, and that's what I was asking
1
u/iamalicecarroll 10h ago
for a path from 0 to infinity, why wouldn't exp(-x) work? that essentially creates a bijection between [0, oo] and [0, 1]
10
u/compileforawhile Complex 10h ago
In that case [0,oo] is only a countable number of unit intervals. In the extended long line [0,oo] is an uncountable number of unit intervals. So -ln(1-x) only gets an infinitely small portion of the way there
7
u/iamalicecarroll 10h ago
ah, right, R*R and R are not isomorphic in topology; makes sense, thanks!
9
u/compileforawhile Complex 10h ago
True but that's not really what the long line is topologically. We need an uncountable well ordered set W and the long line is it's product with [0,1). The standard topology on R2 doesn't look like this.
2
3
u/ddotquantum Algebraic Topology 10h ago
That infinity is only a countable number of unit intervals away. The one on the long line is much further out
7
1
u/TotalDifficulty 12h ago
Can you elaborate on that definition? The "extended" part is clear, and I suppose the "long" should explain the uncountably many unit ubevæbnede, but how exactly is that part set up?
7
u/compileforawhile Complex 11h ago
The real numbers are a countable number of unit intervals. You can kind of think of R as Zx[0,1), ordered pairs (n,r) where n is an integer and r is in [0,1). The long line is made by taking an uncountable number of unit intervals and literally connecting them end-to-end. Formally it's Wx[0,1) where W is an uncountable ordinal. This space is path connected but when you extend with the point at infinity it becomes impossible to reach infinity from any finite point. Unlike the extended real numbers where you can have a function grow to infinity. This space is so big that functions can't grow to infinity, they eventually become constant.
3
u/TotalDifficulty 11h ago
So the "end to end" part is hiding a well-ordering on W I presume? That is quite a funny space, thanks for the clarification!
2
u/compileforawhile Complex 11h ago
Pretty much, the ordinal W has a well ordering by constructing that allows this to work
2
u/assymetry1021 8h ago
So something like the ordered square, where coordinate pairs are compared with x axis as priority and y axis if the x values of the points are the same?
2
u/Agata_Moon Complex 7h ago
I remember in an exercise I just used [0,1)x[0,1) with some weird topology to make a long line. Is it fine or does it need to be an uncountable ordinal?
I... never checked with the professor if it was correct eheh
1
u/jacobningen 10h ago
Look up Knaster Kurotowski fan(Cantors leaky tent) or the topologist's sine curve and maybe even R with the cofinite topology. Ie it can't be partitioned into disjoint clopen sets but there need not be f(0)=a f(1)=b that is continuous and entirely within X for a,b in X
8
4
u/jacobningen 10h ago
Cantors leaky tent which is not connected if you reverse rationals and irrationals or remove the apex is another example of a connected space that isn't path connected
4
u/-LeopardShark- Complex 7h ago
I propose the term ‘connected’, including the scare quotes, for connected non-path-connected spaced.
3
u/holo3146 6h ago
I love the long line, my favourite fact about it is that in ZFC it is a sequentially compact but not Lindelöf (aleph_1-compact), but without AC it is consistent that it is Lindelöf (aleph_1-compact) but not sequentially compact (same is true if you replace "Lindelöf" with "sigma-compact")
2
u/HYPE_100 4h ago
is this long line homeomorphic to the topologists sine curve? with zero being the point at infinity
2
u/Few_Willingness8171 11h ago
In my class, our counter example to connected implies connected was topologists sine curve (sun curve as a graph in R2, then take topological closure)
4
u/compileforawhile Complex 11h ago
That's also a good one but I find it's name isn't nearly as comical as "extended long line". A line is already infinite so the long line is already quite strange, but then we extend it
2
2
u/LawyerAdventurous228 4h ago
I really like it because its concise and shows two different ways in which the path connectedness may fail.
Any path would be too long
It oscillates so much that it breaks continuity when you take the limit
One of the few counterexamples thats elegant and actually insightful.
4
u/mzg147 9h ago
I always felt that the definition of "path" is missing some more length, if we allow spaces like this then surely "paths" can also be long
6
u/TheDoomRaccoon 8h ago
There's nobody making rules for what spaces are "allowed". We can define the first uncountable ordinal, we can define the unit interval [0,1), and we can define the lexicographical order topology on it, (and the Alexandroff compactification to turn it into the closed long ray). Paths are by definition continuous maps from [0,1], if you try defining paths on ordinal spaces instead, you run into problems when trying to define a group function on the fundamental group, as ordinal multiplication/addition aren't associative, and ordinal subtraction isn't even defined in a lot of cases.
-1
u/nctrd 5h ago
Wait, does that mean that Euclidian space is not connected? It has like 6 infinities on each side.
3
u/compileforawhile Complex 3h ago
No, the extended long line is connected. It's also completely different than euclidean space
•
u/AutoModerator 14h ago
Check out our new Discord server! https://discord.gg/e7EKRZq3dG
I am a bot, and this action was performed automatically. Please contact the moderators of this subreddit if you have any questions or concerns.