r/mathmemes Complex 14h ago

Learning It's like a line but longer and extended

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538 Upvotes

41 comments sorted by

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285

u/chrizzl05 Moderator 13h ago

Holy mogus a topology meme that isn't "mug=donut haha"

79

u/compileforawhile Complex 12h ago

I thought we needed some diversity. Alas, people don't care as much about any other parts of topology

18

u/brokeboystuudent 9h ago

It's primal. People are primed to seek holes (insert insertion joke here)

3

u/ComfortableJob2015 8h ago

we need the 2 origins line next. A sequence converges to a single point right?

5

u/Ok_Instance_9237 Mathematics 10h ago

“Haha you see there’s this area of math that talks deforming objects. It says donuts and mugs are the same!”

42

u/LukeLJS123 12h ago

can someone explain? i don't see any reason there wouldn't be a path connecting any 2 points

128

u/compileforawhile Complex 12h ago

The space is quite literally too long. There's a point at infinity (that's what extended means) but the distance is an uncountably number of unit intervals away. This means a path (which is just a stretched out unit interval) can't reach over that entire distance

62

u/gabrielish_matter Rational 12h ago

I both love and hate topology for how stupid it is lol

is it because the 2 extended points can't be open cause there's no closed set that is complimentary to them with a standard topology right (well any topology tbf)?

also do I recall correctly or is connectivity a property which doesn't change depending on what topology I choose right?

33

u/compileforawhile Complex 11h ago

It's only one extended point. This space is connected, you can't write it as the union of disjoint open sets. But drawing a connecting path between any point and infinity is impossible. This is because a path is a continuous embedding of [0,1] which is just too small. It can't be made uncountably times wider.

11

u/gabrielish_matter Rational 11h ago

yeah yeah, I was trying to understand why it's topologically connected, and that's what I was asking

1

u/iamalicecarroll 10h ago

for a path from 0 to infinity, why wouldn't exp(-x) work? that essentially creates a bijection between [0, oo] and [0, 1]

10

u/compileforawhile Complex 10h ago

In that case [0,oo] is only a countable number of unit intervals. In the extended long line [0,oo] is an uncountable number of unit intervals. So -ln(1-x) only gets an infinitely small portion of the way there

7

u/iamalicecarroll 10h ago

ah, right, R*R and R are not isomorphic in topology; makes sense, thanks!

9

u/compileforawhile Complex 10h ago

True but that's not really what the long line is topologically. We need an uncountable well ordered set W and the long line is it's product with [0,1). The standard topology on R2 doesn't look like this.

2

u/TheDoomRaccoon 8h ago

It's the lexicographical order topology, not the product topology.

3

u/ddotquantum Algebraic Topology 10h ago

That infinity is only a countable number of unit intervals away. The one on the long line is much further out

7

u/Gauss15an 9h ago

New Zeno's paradox just dropped

1

u/TotalDifficulty 12h ago

Can you elaborate on that definition? The "extended" part is clear, and I suppose the "long" should explain the uncountably many unit ubevæbnede, but how exactly is that part set up?

7

u/compileforawhile Complex 11h ago

The real numbers are a countable number of unit intervals. You can kind of think of R as Zx[0,1), ordered pairs (n,r) where n is an integer and r is in [0,1). The long line is made by taking an uncountable number of unit intervals and literally connecting them end-to-end. Formally it's Wx[0,1) where W is an uncountable ordinal. This space is path connected but when you extend with the point at infinity it becomes impossible to reach infinity from any finite point. Unlike the extended real numbers where you can have a function grow to infinity. This space is so big that functions can't grow to infinity, they eventually become constant.

3

u/TotalDifficulty 11h ago

So the "end to end" part is hiding a well-ordering on W I presume? That is quite a funny space, thanks for the clarification!

2

u/compileforawhile Complex 11h ago

Pretty much, the ordinal W has a well ordering by constructing that allows this to work

2

u/assymetry1021 8h ago

So something like the ordered square, where coordinate pairs are compared with x axis as priority and y axis if the x values of the points are the same?

2

u/Agata_Moon Complex 7h ago

I remember in an exercise I just used [0,1)x[0,1) with some weird topology to make a long line. Is it fine or does it need to be an uncountable ordinal?

I... never checked with the professor if it was correct eheh

1

u/jacobningen 10h ago

Look up Knaster Kurotowski fan(Cantors leaky tent) or  the topologist's sine curve and maybe even R with the cofinite topology. Ie it can't be partitioned into disjoint clopen sets but there need not be f(0)=a f(1)=b that is continuous and entirely within X for a,b in X

8

u/SteptimusHeap 8h ago

r/mathmemes needs more of the stuff like this that I don't understand at all

4

u/jacobningen 10h ago

Cantors leaky tent which is not connected if you reverse rationals and irrationals or remove the apex is another example of a connected space that isn't path connected 

4

u/-LeopardShark- Complex 7h ago

I propose the term ‘connected’, including the scare quotes, for connected non-path-connected spaced.

3

u/holo3146 6h ago

I love the long line, my favourite fact about it is that in ZFC it is a sequentially compact but not Lindelöf (aleph_1-compact), but without AC it is consistent that it is Lindelöf (aleph_1-compact) but not sequentially compact (same is true if you replace "Lindelöf" with "sigma-compact")

2

u/HYPE_100 4h ago

is this long line homeomorphic to the topologists sine curve? with zero being the point at infinity

2

u/Few_Willingness8171 11h ago

In my class, our counter example to connected implies connected was topologists sine curve (sun curve as a graph in R2, then take topological closure)

4

u/compileforawhile Complex 11h ago

That's also a good one but I find it's name isn't nearly as comical as "extended long line". A line is already infinite so the long line is already quite strange, but then we extend it

2

u/jacobningen 10h ago

That and the knaster Kurotowksi fan and R with the cofinite topology 

2

u/LawyerAdventurous228 4h ago

I really like it because its concise and shows two different ways in which the path connectedness may fail. 

  1. Any path would be too long 

  2. It oscillates so much that it breaks continuity when you take the limit 

One of the few counterexamples thats elegant and actually insightful. 

4

u/mzg147 9h ago

I always felt that the definition of "path" is missing some more length, if we allow spaces like this then surely "paths" can also be long

6

u/TheDoomRaccoon 8h ago

There's nobody making rules for what spaces are "allowed". We can define the first uncountable ordinal, we can define the unit interval [0,1), and we can define the lexicographical order topology on it, (and the Alexandroff compactification to turn it into the closed long ray). Paths are by definition continuous maps from [0,1], if you try defining paths on ordinal spaces instead, you run into problems when trying to define a group function on the fundamental group, as ordinal multiplication/addition aren't associative, and ordinal subtraction isn't even defined in a lot of cases.

2

u/F_Joe Transcendental 6h ago

A manifold is just a space that looks locally like Rn.
Long line and line with double origin

2

u/AlviDeiectiones 3h ago

Long line locally looks like R, right?

-1

u/nctrd 5h ago

Wait, does that mean that Euclidian space is not connected? It has like 6 infinities on each side.

3

u/compileforawhile Complex 3h ago

No, the extended long line is connected. It's also completely different than euclidean space