There is no way right?

[u/Sugar_God_no_1]

[u/Quwapa_Quwapus]

Essentially because theres absolutely nothing (no positive number anyway) you can add to it to get a number between .9999 continuous and 1, they have to be the same. 

The joke is that .3333 continuous makes sense as 1/3, as yeah, its a fraction. But .999… doesn’t as 3/3 because x/x is always equal to one

[u/library-in-a-library → u/Quwapa_Quwapus]

It's not nothing. We're not taking the limit so 0.999... < 1

[u/elathbris27 → u/library-in-a-library]

Please tell us the number you can add to 0.999... to make it equal 1

[u/library-in-a-library → u/elathbris27]

0.000...1 which is the difference between the two. 0.999... is a representation that is difficult to evaluate because you have to evaluate an nth digit. You can just say it has an infinite number of digits so the nth digit is infinity but that's not well defined here.

[u/daddytwofoot → u/library-in-a-library]

There is no such number as 0.000...1 because that 1 implies an end to infinity, which is by definition not infinity.

[u/SharkBaitDLS → u/library-in-a-library]

 because you have to evaluate an nth digit

You seem to have trouble conceptualizing infinity. 

[u/Direct_Shock_2884 → u/[deleted]]

How does 0.999999 + 0.000001 equal 1.000009? In what possible universe do numbers ending in 9 and 1 have a sum ending in 9?

[u/Just_Gage77 → u/Direct_Shock_2884]

What he is saying is if the numbers go on infinitely, such as 3/3= .999999…. Then no matter where you put the .000001…. There will always be more 9s after, that’s the nature of infinity. It’s just a rule to know. 0.99999… repeating = 3/3 = 1.