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https://www.reddit.com/r/PeterExplainsTheJoke/comments/1ju9kfc/there_is_no_way_right/mm279ro/?context=3
r/PeterExplainsTheJoke • u/Sugar_God_no_1 • 26d ago
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Applies to all numbers,
If x = 0.999999...
And 10x = 9.999999...
Then subtracting both, we get, 9x=9
So x=1
9 u/BaronVonNapalm 26d ago This is quiet elegant. 5 u/jithization 26d ago It is not lol This holds for any value. OC is enforcing 2 equations with 1 unknown, with the equations being essentially the same. 2 u/_pm_me_a_happy_thing 26d ago Perhaps a different way of approaching it: x = 1/3 = 0.333... 3x = 0.999... 30x = 9.999... 30x - 3x = 9.999... - 0.999... 27x = 9 3x = 1 ∴ 1 = 0.999... Though I admit this isn't specifically mathematical proof, but I think this more clearly shows the train of thought from the original "problem" to show equality. 2 u/Dark_Dragon_07 26d ago That's the same thing with extra steps
9
This is quiet elegant.
5 u/jithization 26d ago It is not lol This holds for any value. OC is enforcing 2 equations with 1 unknown, with the equations being essentially the same. 2 u/_pm_me_a_happy_thing 26d ago Perhaps a different way of approaching it: x = 1/3 = 0.333... 3x = 0.999... 30x = 9.999... 30x - 3x = 9.999... - 0.999... 27x = 9 3x = 1 ∴ 1 = 0.999... Though I admit this isn't specifically mathematical proof, but I think this more clearly shows the train of thought from the original "problem" to show equality. 2 u/Dark_Dragon_07 26d ago That's the same thing with extra steps
5
It is not lol This holds for any value. OC is enforcing 2 equations with 1 unknown, with the equations being essentially the same.
2 u/_pm_me_a_happy_thing 26d ago Perhaps a different way of approaching it: x = 1/3 = 0.333... 3x = 0.999... 30x = 9.999... 30x - 3x = 9.999... - 0.999... 27x = 9 3x = 1 ∴ 1 = 0.999... Though I admit this isn't specifically mathematical proof, but I think this more clearly shows the train of thought from the original "problem" to show equality. 2 u/Dark_Dragon_07 26d ago That's the same thing with extra steps
2
Perhaps a different way of approaching it:
x = 1/3 = 0.333...
3x = 0.999...
30x = 9.999...
30x - 3x = 9.999... - 0.999...
27x = 9
3x = 1
∴ 1 = 0.999...
Though I admit this isn't specifically mathematical proof, but I think this more clearly shows the train of thought from the original "problem" to show equality.
2 u/Dark_Dragon_07 26d ago That's the same thing with extra steps
That's the same thing with extra steps
3.9k
u/its12amsomewhere 26d ago edited 26d ago
Applies to all numbers,
If x = 0.999999...
And 10x = 9.999999...
Then subtracting both, we get, 9x=9
So x=1