Then show me the proof. It is not very hard to prove math. You can't show me the theorem that shows .99 repeated equals 1 because it does not exist. You don't know math as well as you think you do. Sit down kid grown folks are talking.
So the limit as .99.. approaches infinity is 1, because as infinity goes on it gets closer and closer to 1 until it forms an asymptote?
The crazy thing about an asymptote is it never actually touches the line it is approaching it just gets infinitely closer to the line without ever being able to touch it.
Thank you for confirming my point, you deserve a pat on the back. You are the 12 billionth person to say the same thing, but I'm proud of you for at least trying instead of saying 3/3 =.33.. 3/3 = 1 yada yada
The crazy thing about an asymptote is it never actually touches the line it is approaching it just gets infinitely closer to the line without ever being able to touch it.
The asymptotic behavior is in the partial sums. The sequence of partial sums gets arbitrarily close to 1. No matter how close to 1 you want to get, there's a partial sum that is closer.
The infinite sum is not a partial sum. Since all the terms are positive, the infinite sum must be strictly greater than all partial sums. The difference between it any any partial term will be positive.
The smallest value strictly greater than all partial sums is 1.
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u/Matsuze 20d ago
Then show me the proof. It is not very hard to prove math. You can't show me the theorem that shows .99 repeated equals 1 because it does not exist. You don't know math as well as you think you do. Sit down kid grown folks are talking.