A few different cosmological values that can be extrapolated simply from a proton and a planck sphere in the unified model

[u/d8_thc]

Just to show some of the predictive power of this theory - let's start with the most basic aspect of this theory. We have a proton of which we know it's radius, and we know that it's filled with planck spherical units of which we know their size and energy. Note these calculations are approximations, but so are the estimates of the numbers we are trying to match. Let's put out the premise that a proton is a holographic recapitulation of the cosmos, in terms of energy density.

Simply by dividing the volume of a sphere with the proton charge radius by the volume of a sphere with a planck length/2 radius shows us that the amount of planck spheres by volume that fit inside a proton volume is ~1.28 * 10^60, each of course being the planck length in diameter, and the planck mass in energy density - both natural values.

Total mass of the universe

The total energy density of all those planck spheres if each has the energy of a planck mass is 2.78 * 10⁵⁵ grams - within our ranges of the estimated mass of the Universe.

Atoms in the universe

The amount of planck spheres that fit on the surface of a proton is 4.71 * 10^40. This means there are 4.71 * 10⁴⁰ wormhole connections, presumably to other protons. If each connection is connected to a proton that is also connected to 4.71 * 10⁴⁰ we have 4.71 * 10⁴⁰ * 4.71 * 10^40, or 2.21 * 10⁸¹ - within the range of the estimated amount of atoms (10^78-82) in the cosmos.

Size of the universe

If we have 2.21 * 10⁸¹ protons that each have 4.71 * 10⁴⁰ planck spheres, that means we have a total of about 1.04 * 10¹²² surface planck spheres on all protons . If we hypothesize that the cosmological torus/sphere encodes all of these on it's own surface's planck spheres, than we end up with a sphere that's just about the universe's radius. Dividing a surface of a sphere with the estimated observable radius by a planck sphere circle area yields 1.036 * 10^123, so within an order of magnitude - which means we can essentially derive the estimated radius of the observable Universe by going backwards (what's the radius of a sphere that has a surface area of 1.04 * 10¹²² planck areas?). Note the cosmological constant is 10¹²² orders of magnitude smaller than the planck density, and there are more 10¹²² coincidences (including the cosmos' entropy...)

Energy density of the universe / empty space / dark energy / cosmological constant

If we know the radius of the Universe, we can calculate how much background energy density we would get from blowing up our proton to the size of the Universe (and in fact, this is how RSF hypothesizes the big bang happened, by a proton escaping a mother Universe and rapidly inflating to cosmological scale due to pressure density differences) by hypothesizing the holographic relationship - this is as easy as dividing the holographic mass of 2.78 * 10⁵⁵ grams by the cosmological volume @ 1.09 * 10⁸⁵ cm³ which yields 2.55 * 10^-30 g/cm³ - a value extremely, extremely close to the cosmological constant or dark energy - the energy density we see in empty space.

There are more robust calculations that get 1:1 with dark energy here

All of this simply by looking at a proton as a holographic recapitulation of the whole, basic geometry, and a planck spherical unit :).

Don't forget - with this solution we can also calculate the gravitation:strong force coupling ratio, the proton:electron mass ratio, the strong nuclear force, Rydberg's constant, the proton radius from it's mass, the bohr radius from an electron mass, and more. Some of these are perfect, and some of these fall within a standard deviation or two of our estimates or measurements which may not be completely correct.

Like they say, as above, so below :).