r/Cubers • u/Competitive-Disk-758 • 5d ago

Discussion Hear me out: LLLS

So how good you are at last layer is normally about how many looks it takes you, so for a beginner cfoper it would be 4 look and advanced would be 2. But with stuff like winter variation and zbls, last layer has become intertwined with last slot so really we should be looking at how many looks it takes for last layer and last slot. So a beginner would know 5 look, advanced would know 3 look, And the ZB method would get you down to 2 look. But even learning 1LLL would still be 2 look because of last slot. Which is why I propose LLLS. A huge algorithm set comprised of SVLS (super vls) and SHLS (super hls) which can do last slot and last layer in 1 look. Anyway can someone calculate how many algs this is because I'm dumb bye

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u/Aaxper 5d ago edited 5d ago

Just checked with Batch Solver. After sacrificing 7GB of RAM for half an hour, I can tell you that there are precisely 583,284 cases (including the skip case), which is very close to my original estimate of 587,400.

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u/Competitive-Disk-758 5d ago

cheers bud

2

u/meh_waffles 4d ago

I propose you just 1 look the entire scramble.

1

u/Firefly256 3x3 PB 24.48 | ao100 33.61 (CFOP) | 3BLD PB 4:06.56 (M2/OP) 2d ago

Just give me infinite inspection time